MCQ
The standard electrode potential are given
$E^o_{Fe^{+2}/Fe} =-0.44\,V$ and $ E^o_{H^+ / O_2 / H_2O} =1.23\, V$
Calculate the $E^o_{cell}$ of the corrosion :- ............. $\mathrm{V}$
- A$-0.79$
- B$-1.67$
- ✓$1.67$
- D$+0.79$
✓
Answer
Correct option: C.
$1.67$
c
${E}_{\text {cell }}^{\circ} ={E}_{\mathrm{C}}^{\circ}-{E}_{\mathrm{a}}^o$
${E}_{\text {cell }}^{\circ} ={E}_{\mathrm{C}}^{\circ}-{E}_{\mathrm{a}}^o$
$=1.23-(-0.44) $
$=1.67 \,\mathrm{V} $
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