MCQ
The standard Gibbs free energy change $\Delta {G^o}$ is related to equilibrium constant ${K_p}$ as
- A${K_p} = - RT\,\ln \,\Delta {G^o}$
- B${K_p} = {\left( {\frac{e}{{RT}}} \right)^{\Delta {G^o}}}$
- C${K_p} = - \frac{{\Delta {G^o}}}{{RT}}$
- ✓${K_p} = {e^{ - \,\frac{{\Delta {G^o}}}{{RT}}}}$

