MCQ
The standard reduction potential data at $25^{\circ} C$ is given below.

$E ^0\left( Fe ^{3+} . Fe ^{2+}\right)=+0.77 V $

$E ^0\left( Fe ^{2+} . Fe \right)=-0.44 V $

$E ^{\circ}\left( Cu ^{2+} . Cu \right)=+0.34 V $

$E ^0\left( Cu ^{+} . Cu \right)=+0.52 V $

$E ^{\circ}\left( O _2( g )+4 H ^{+}+4 e ^{-} \rightarrow 2 H _2 O \right)=+1.23 V $

$E ^{\circ}\left( O _2( g )+2 H _2 O +4 e ^{-} \rightarrow 4 OH \right)=+0.40 V $

$E ^0\left( Cr ^{3+} . Cr \right)=-0.74 V $

$E ^{\circ}\left( Cr ^{2+} . Cr \right)=-0.91 V$

Match $E ^{\circ}$ of the rebox pair in List $I$ with the values given in List $II$ and select the correct answer using the code given below the lists:

List $I$ List $II$
$P.$ $\quad E ^{\circ}\left( Fe ^{3+}, Fe \right)$ $1.$ $\quad-0.18 V$
$Q.$ $\quad E ^{\circ}\left(4 H _2 O \rightleftharpoons 4 H ^{+}+4 OH ^{-}\right)$ $2.$ $\quad-0.4 V$
$R.$ $\quad E ^{\circ}\left( Cu ^{2+}+ Cu \rightarrow 2 Cu ^{+}\right)$ $3.$ $\quad-0.04 V$
$S.$ $\quad E ^{\circ}\left( Cr ^{3+}, Cr ^{+2}\right)$ $4.$ $\quad-0.83 V$

Codes: $ \quad P \quad Q \quad R \quad S $ 

  • A
    $\quad 4 \quad 1 \quad 2 \quad 3 $
  • B
    $\quad 2 \quad 3 \quad 4 \quad 1 $
  • C
    $\quad 1 \quad 2 \quad 3 \quad 4 $
  • $\quad 3 \quad 4 \quad 1 \quad 2 $

Answer

Correct option: D.
$\quad 3 \quad 4 \quad 1 \quad 2 $
d
$(P)$  $Image$

$\Rightarrow $$ 1 \times 0.77+2 \times(-0.44)=3 \times x $

$\Rightarrow $$ x=-\frac{0.11}{3} V \simeq-0.04 V .$

$(Q)$ $\quad 4 H _2 O \rightleftharpoons 4 H ^{+}+4 OH ^{-}$

$Image$

$(R)$ $Image$

$x \times 1+0.52 \times 1=0.34 \times 2 $

$x=0.16 V$

$Image$

However, in the given option, $-0.18 V$ is printed.

$(S)$  $Image$

$x \times 1+2 \times(-0.91)=3 \times(-0.74) $

$x-1.82=-2.22 $

$x=-0.4 V$

Hence, most appropriate is $(D)$.

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