MCQ
The temperature of the body is increased from $-73^o C\, to \,327^o C$, the ratio of energy emitted per second is :
- A$1:3$
- ✓$1:81$
- C$1:27$
- D$ 1:9$
${T_2} = 327 + 273 = 600\;K$
Energy per second $P\left( { = \frac{Q}{t}} \right) \propto {T^4}$
$\Rightarrow \frac{{{P_2}}}{{{P_1}}} = {\left( {\frac{{{T_2}}}{{{T_1}}}} \right)^4} = {\left( {\frac{{600}}{{200}}} \right)^2} = 81$
$\frac{{{P_1}}}{{{P_2}}} = \frac{1}{{81}}$
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[Latent heat of ice is $3.4 \times 10^{5}\; J / k g$ and $g=10\; N / kg ]$