$\mathrm{t}_{1}=20^{\circ} \mathrm{C} \pm 0.5^{\circ} \mathrm{C}$
$\mathrm{t}_{2}=50^{\circ} \mathrm{C} \pm 0.5^{\circ} \mathrm{C}$
The temperature difference of two bodies is
$\mathrm{t}=\mathrm{t}_{2}-\mathrm{t}_{1}=50^{\circ} \mathrm{C}-20^{\circ}=30^{\circ} \mathrm{C}$
The error in temperature differerence is given by
$\Delta \mathrm{t}=\left(\Delta \mathrm{t}_{1}+\Delta \mathrm{t}_{2}\right)$
$=\left(0.5^{\circ} \mathrm{C}+0.5^{\circ} \mathrm{C}\right)=1^{\circ} \mathrm{C}$
The temperature difference is $30^{\circ} \mathrm{C} \pm 1^{\circ} \mathrm{C}$
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| Column $-I$ | Column $-II$ |
|
$(a)$ Stress is proportional to strain. |
$(i)$ Elastic limit |
| $(b)$ When the load of the wire is removed, the body does regain its original dimension. | $(ii)$ Limit of pro-portionality |
| $(iii)$ Plastic deformation |
