The terminal velocity $\left( v _{ t }\right)$ of the spherical rain drop depends on the radius ( $r$ ) of the spherical rain drop as
JEE MAIN 2022, Easy
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$v _{ t }=\frac{2}{9} \frac{ gr ^{2}\left(\rho_{ p }-\rho_{1}\right)}{\eta} ; \quad v _{ t } \propto r ^{2}$
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