The thermal conductivity of a material in $CGS$ system is $0.4$ . In steady state, the rate of flow of heat $10 cal/sec-cm2$ , then the thermal gradient will be ....... $^oC/cm$
Medium
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(c) $\frac{{\Delta Q}}{{\Delta t}} = \frac{{KA\,\Delta \theta }}{{\Delta x}}$ ==> Thermal gradient $\frac{{\Delta \theta }}{{\Delta x}}$
$ = \frac{{(\Delta Q/\Delta t)}}{K} = \frac{{10}}{{0.4}} = 25^\circ C/cm$
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