The translational degrees of freedom $(f)$ and rotational degrees of freedom $(f)$ of $\mathrm{CH}_4$ molecule are:
A$f=2$ and $f=2$
B$f_t=3$ and $f=3$
C$f=3$ and $f=2$
D$f=2$ and $f=3$
JEE MAIN 2024, Diffcult
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B$f_t=3$ and $f=3$
b $\text { Since } \mathrm{CH}_4 \text { is polyatomic Non-Linear }$
$\text { D.O.F of } \mathrm{CH}_4$
$\text { T. DOF }=3$
$\text { R DOF }=3$
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