The two ends of a rod of length $L$ and a uniform cross-sectional area $A$ are kept at two temperatures $T_1$ and $T_2 (T_1 > T_2)$. The rate of heat transfer,$\frac{ dQ }{dt}$, through the rod in a steady state is given by
AIPMT 2009,AIIMS 2019, Easy
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$Similar\,to\,I = V/R$
$\frac{{dQ}}{{dt}} = \frac{{kA}}{L}\left( {{T_1} - {T_2}} \right)$
$k=conductivity\,of\,the\,rod.$
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