Question
The unit of length convenient on the nuclear scale is a fermi: 1 $f = 10^{–15}m$. Nuclear sizes obey roughly the following empirical relation:$\text{r}=\text{r}_0\text{A}^{1/3}$
where r is the radius of the nucleus, A its mass number, and r o is a constant equal to about, 1.2 f. Show that the rule implies that nuclear mass density is nearly constant for different nuclei. Estimate the mass density of sodium nucleus. Compare it with the average mass density of a sodium atom obtained in Exercise. 2.27.

Answer

Radius of nucleus r is given by the relation,$\text{r}=\text{r}_0\text{A}^{1/3}\ \dots(\text{i})$
$r_0= 1.2 f = 1.2 \times 10^{-15}m$ Volume of nucleus, $\text{V}=\frac{1}{3}\pi\text{r}^3$$=\frac{1}{3}\pi(\text{r}_0\text{A}^{1/3})^3=\frac{1}{3}\pi\text{r}_0^3\text{A}\ \dots(\text{ii})$
Now, the mass of a nuclei M is equal to its mass number i.e., M = A amu = $A \times 1.66 \times 10^{-27}kg$ Density of nucleus, p = Mass of nucleus/Volume of nucleus$=\frac{\text{A}\times1.66\times10^{-27}}{\frac{4}{3}\pi\text{r}_0^3\text{A}}=\frac{3\times1.66\times10^{-27}}{4\pi\text{r}_0^3}\text{kg/m}^3$
This relation shows that nuclear mass depends only on constant $r_0$. Hence, the nuclear mass densities of all nuclei are nearly the same. Density of sodium nucleus is given by,$\rho_\text{sodium}=\frac{3\times1.66\times10^{-27}}{4\times3.14\times(1.2\times10^{-15})^3}$
$=\Big(\frac{4.98}{21.71}\Big)\times10^{-18}$
$=2.29\times10^{-17}\text{kg m}^{-3}$

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