The upper end of a wire of radius $4\, mm$ and length $100\, cm$ is clamped and its other end is twisted through an angle of $30°$. Then angle of shear is ..... $^o$
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(b) Angle of shear $\varphi = \frac{{r\theta }}{L}$$ = \frac{{4 \times {{10}^{ - 1}}}}{{100}} \times {30^o} = {0.12^o}$
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