A $100\,m$ long wire having cross-sectional area $6.25 \times 10^{-4}\,m ^2$ and Young's modulus is $10^{10}\,Nm ^{-2}$ is subjected to a load of $250\,N$, then the elongation in the wire will be :
JEE MAIN 2023, Easy
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Elongation in wire $\delta=\frac{ F \ell}{ AY }$
$\delta=\frac{250 \times 100}{6.25 \times 10^{-4} \times 10^{10}}$
$\delta=4 \times 10^{-3}\,m$
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