MCQ
The value of current through the $20\,\Omega $ resistor is ............ $amp$
- ✓$0.6$
- B$0.8$
- C$1.2$
- D$1.8$
✓
Answer
Correct option: A.
$0.6$
a
$\frac{x-10}{10}+\frac{x+6}{20}+\frac{x}{10}+\frac{x-10}{5}=0$
$\frac{x-10}{10}+\frac{x+6}{20}+\frac{x}{10}+\frac{x-10}{5}=0$
$\Rightarrow \mathrm{x}=6 \mathrm{\,V}$
$\therefore \mathrm{I}_{20 \Omega}=\frac{6+6}{20}=0.6 \mathrm{\,Amp}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
An elementary particle of mass $m$ and charge $+e$ is projected with velocity $v$ at a much more massive particle of charge $Ze$, where $Z > 0$. What is the closest possible approach of the incident particle
→A thin wire of length $2\,m$ is placed perpendicular to the $x-y$ plane. It is moved with velocity $\overrightarrow v = \left( {2\hat i + 3\hat j + \hat k} \right)\,m/s$ through a region of magnetic induction $\overrightarrow B = \left( {\hat i + 2\hat j} \right)\,wb/{m^2} .$ The potential difference induced between the ends of the wire is......$volts$
→A conducting loop carrying a current $I$ is placed in a uniform magnetic field pointing into the plane of the paper as shown. The loop will have a tendency to
→A coil of inductance 40 henry is connected in 0series with a resistance of 8 ohm and the combination is joined to the terminals of a 2 volt battery. The time constant of the circuit is
In a full wave rectifiers, input ac current has a frequency $‘v’$. The output frequency of current is
→What will be the nature of charge on the metal paper clip of electroscope when a negatively charged body is brought in contact with it?
In the given circuit the current through Zener Diode is close to.......$mA$
→Whenever the magnetic flux linked with a coil changes, an induced e.m.f. is produced in the circuit. The $e.m.f.$ lasts
→A charge particle is free to move in an electric field. It will travel
Two uncharged bodies on rubbing, get charged due to: