MCQ
The value of $\Delta S$ for freezing of $10\,g$ of $H_2O(l)$ (enthalpy of fusion is $80 \, cal/g$) at $0\,^oC$ and $1\, atm$ pressure is.......$J/K$
- A$12.25$
- B$-0.244 $
- C$-2.93$
- ✓$-12.25 $
✓
Answer
Correct option: D.
$-12.25 $
d
$\Delta S_{\text {freezing }}=-\frac{\Delta H_{\text {fusion }}}{T}$
$\Delta S_{\text {freezing }}=-\frac{\Delta H_{\text {fusion }}}{T}$
$\Delta S=-\frac{80 \times 10}{273}$
${=-2.93\, \mathrm{Cal} / \mathrm{K}}$
${=-12.25\, \mathrm{J} / \mathrm{K}}$
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