MCQ
The Van't Hoff factor will be highest for
- ASodium chloride
- BMagnesium chloride
- ✓Sodium phosphate
- DUrea
✓
Answer
Correct option: C.
Sodium phosphate
c
(c)$N{a_3}P{O_4}$ gives maximum four ion it is show highest Vant’s haff factor.
(c)$N{a_3}P{O_4}$ gives maximum four ion it is show highest Vant’s haff factor.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
By doubling the initial concentration of reactant in a reaction, the half-life of that reaction also doubles as compared to before, then the order of this reaction will be :
In the following members of transition elements, the lowest ionization energy is of
The correct order of spin only magnetic moments for the following complex ions is
Which of the following ligand forms maximum number of $5$ membered ring with central metal atom :-
→Above compounds can be differentiated by following reagent
In basic medium $CrO _{4}^{2-}$ oxidises $S _{2} O _{3}^{2-}$ to form $SO _{4}^{2-}$ and itself changes into $Cr ( OH )_{4}^{-}$. The volume of $0.154\, M CrO _{4}^{2-}$ required to react with $40\, mL$ of $0.25\, M S _{2} O _{3}^{2-}$ is ........... $mL$
→(Rounded-off to the nearest integer)
Which of the following compounds react with $NaHCO _3$ :
→Correct order of bond angle in given species is
The product of mustard oil reaction is
The total number of unpaired electrons present in $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{2}$ and $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}$ is $......$
→