The variations of potential energy $(U)$ with position $x$ for three simple harmonic oscillators $A, B$ and $C$ are shown in figure. The oscillators have same mass. The time period of oscillation is greatest for
Medium
Download our app for free and get startedPlay store
(c)

$U=\frac{1}{2} k x^2$

$x^2=\frac{2 U}{k}$

or $x \propto \frac{1}{k}$ (Since $U$ is constant)

Also $T=2 \pi \sqrt{\frac{m}{k}}$

or $T \propto \frac{1}{\sqrt{k}}$

Therefore $x \propto T$

Hence the oscillation with maximum $x$ will have the maximum time period.

art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    The kinetic energy of a particle executing $S.H.M.$ is $16\, J$ when it is at its mean position. If the mass of the particle is $0.32 \,kg$, then what is the maximum velocity of the particle ..... $m/s$
    View Solution
  • 2
    A particle is performing simple harmonic motion
    $(i)$ its velocity-displacement graph is parabolic in nature
    $(ii)$ its velocity-time graph is sinusoidal in nature
    $(iii)$ its velocity-acceleration graph is elliptical in nature
    Correct answer is
    View Solution
  • 3
    A mass $m$ is attached to two springs of same force constant $K$, as shown in following four arrangements. If $T_1, T_2, T_3$ and $T_4$ respectively be the time periods of oscillation in the following arrangements, in which case time period is maximum?
    View Solution
  • 4
    The function $sin^2\,(\omega t)$ represents
    View Solution
  • 5
    A particle of mass m is attached to a spring (of spring constant k) and has a natural angular frequency ${\omega _0}$ - An external force $F (t)$ proportional to $\cos \omega \,t((\omega \ne {\omega _0})$ is applied to the oscillator. The time displacement of the oscillator will be proportional to
    View Solution
  • 6
    A body oscillates with a simple harmonic motion having amplitude $0.05\, m .$ At a certain instant, its displacement is $0.01\, m$ and acceleration is $1.0 \,m / s ^{2} .$ The period of oscillation is
    View Solution
  • 7
    When a particle of mass $m$ moves on the $x$-axis in a potential of the form $V(x)=\mathrm{kx}^2$ it performs simple harmonic motion. The corresponding time period is proportional to $\sqrt{\frac{\mathrm{m}}{\mathrm{k}}}$, as can be seen easily using dimensional analysis. However, the motion of a particle can be periodic even when its potential energy increases on both sides of $\mathrm{x}=0$ in a way different from $\mathrm{kx}^2$ and its total energy is such that the particle does not escape to infinity. Consider a particle of mass $\mathrm{m}$ moving on the $x$-axis. Its potential energy is $V(x)=\alpha x^4(\alpha>0)$ for $|x|$ near the origin and becomes a constant equal to $\mathrm{V}_0$ for $|x| \geq X_0$ (see figure). $Image$

    $1.$ If the total energy of the particle is $E$, it will perform periodic motion only if

    $(A)$ $E$ $<0$ $(B)$ $E$ $>0$ $(C)$ $\mathrm{V}_0 > \mathrm{E}>0$ $(D)$ $E > V_0$

    $2.$ For periodic motion of small amplitude $\mathrm{A}$, the time period $\mathrm{T}$ of this particle is proportional to

    $(A)$ $\mathrm{A} \sqrt{\frac{\mathrm{m}}{\alpha}}$ $(B)$ $\frac{1}{\mathrm{~A}} \sqrt{\frac{\mathrm{m}}{\alpha}}$ $(C)$ $\mathrm{A} \sqrt{\frac{\alpha}{\mathrm{m}}}$ $(D)$ $\mathrm{A} \sqrt{\frac{\alpha}{\mathrm{m}}}$

    $3.$ The acceleration of this particle for $|\mathrm{x}|>\mathrm{X}_0$ is

    $(A)$ proportional to $\mathrm{V}_0$

    $(B)$ proportional to $\frac{\mathrm{V}_0}{\mathrm{mX}_0}$

    $(C)$ proportional to $\sqrt{\frac{\mathrm{V}_0}{\mathrm{mX}_0}}$

    $(D)$ zero

    Give the answer qustion $1,2$ and $3.$

    View Solution
  • 8
    Two parallel discs are connected by a rigid rod of length $L=0.5 \,m$ centrally. Each disc has a slit oppositely placed as shown in the figure. A beam of neutral atoms are incident on one of the discs axially at different velocities $v$, while the system is rotated at angular speed of $600 \,rev / second$, so that atoms only with a specific velocity emerge at the other end. Calculate the two largest speeds (in metre/second) of the atoms that will emerge at the other end.
    View Solution
  • 9
    A heavy small-sized sphere is suspended by a string of length $l$. The sphere rotates uniformly in a horizontal circle with the string making an angle $\theta $ with the vertical. Then the time period of this conical pendulum is
    View Solution
  • 10
    The potential energy of a particle of mass $100 \,g$ moving along $x$-axis is given by $U=5 x(x-4)$, where $x$ is in metre. The period of oscillation is .................
    View Solution