MCQ
The vecter term of coulomb's law is :
  • $\vec{F}=\frac{1}{4\pi\in_{0}}\frac{q_{1}q_{2}}{|\vec{r}|^{3}}\vec{r}$
  • B
    $\vec{F}=\frac{1}{4\pi\in_{0}}\frac{q_{1}q_{2}}{|\vec{r}|^{3}}$
  • C
    $\overrightarrow{ F }=\frac{1}{4 \pi \varepsilon_0} \frac{q_1 q_2}{r^2}$
  • D
    $\vec{F}=\frac{1}{4\pi\in_{0}}\frac{q_{1}q_{2}}{|\vec{r}|^{2}}\vec{r}$

Answer

Correct option: A.
$\vec{F}=\frac{1}{4\pi\in_{0}}\frac{q_{1}q_{2}}{|\vec{r}|^{3}}\vec{r}$
A

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