MCQ
The velocity of waves in a string fixed at both ends is $2 m/s$. The string forms standing waves with nodes $5.0 cm$ apart. The frequency of vibration of the string in $Hz$ is
- A$40$
- B$30$
- ✓$20$
- D$10$
✓
Answer
Correct option: C.
$20$
c
(c) Here $\frac{\lambda }{2} = 5.0\,cm\,\,$$ \Rightarrow \lambda = 10$$cm$
Hence $n = \frac{v}{\lambda } = \frac{{200}}{{10}} = 20\,Hz.$
(c) Here $\frac{\lambda }{2} = 5.0\,cm\,\,$$ \Rightarrow \lambda = 10$$cm$
Hence $n = \frac{v}{\lambda } = \frac{{200}}{{10}} = 20\,Hz.$
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