The volume occupied by the molecules contained in $4.5\,kg$ water at $STP$, if the intermolecular forces vanish away is ........ $m ^{3}$
A$5.6 \times 10^{3}$
B$5.6 \times 10^{-3}$
C$5.6$
D$5.6 \times 10^{6}$
NEET 2022, Easy
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C$5.6$
c $V =$ (no. of moles) ($22.4$ litre)
$=\frac{\text { mass }}{\text { molar mass }}\left(22.4 \times 10^{-3} m ^{3}\right)$
$=\frac{4.5 \times 10^{3}}{18} \times 22.4 \times 10^{-3} m ^{3}$
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