The weight of a body in water is one third of its weight in air. The density of the body is ....... $g / cm ^3$
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(b)
Given,
Weight of body in water is $\frac{1}{3}$ of total weight in air,
Mean, buoyancy force in water is $\frac{2}{3}$ of total weight in air
Volume of body, $V$
Density of water and body, $\rho_w\ and\, \rho_b$
Apply Archimedes principle
Buoyancy force $=$ weight of water displaces $=\frac{2}{3}$ weight of body in air
$\rho_{ w } Vg =\frac{2}{3} \rho_{ b } Vg$
$\rho_{ b }=1.5 \rho_{ w }$
Density of body is $1.5$ time the density of water.
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