Question
The weight of an empty boat is 500 kg. When it floats 1/3 part of its sink in water. Find out what is the maximum weight can be loaded on the boat?

Answer

Let the rolume of the boat be $V m ^3$ and the density of water be $\rho$.
Since boat is empty V/3 part is sink in water. Hence, the weight of water removed by the submerged part
$=\frac{V}{3} \times \rho \times g$ of the boat.
From principle of floating
Weight of boat = Weight of water removed by the boat
$\begin{array}{l}\Rightarrow \quad 500 \times g=\frac{V \rho g}{3} \\\Rightarrow \quad 1500 g=V \rho g\ldots\ldots (1)\end{array}$
Let the maximum weight can be loaded on the boat be W kg . Then weight of water removed by the boat is equal to the total weight of the boat.
i.e. the volume of water removed will be equal to the total volume of the boat.
Hence, $( W +500) g = V \rho g\dots\ldots (2)$
Compare eq. (1) and (2)
$\begin{aligned}(W+500) g & =1500 g \\W & =1500-500=1000 kg\end{aligned}$
Therefore maximum weight on the boat is 1000 kg can be loaded.

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