Question
The work done to move a charge along an equipotential from $A$ to $B:$
✓
Answer
- Must be defined as $-\int\limits_\text{A}^\text{B}\text{E}.\text{dl}$.
- Is zero.
Work done in moving a charge particle from point $A$ to point $B$ is given by $W_{AB} = q(V_B - V_A)$ and the line integral of electrical field from point $A$ to $B$ gives potential difference i.e., $\text{V}_\text{B}-\text{V}_\text{A}=-\int\limits_\text{A}^\text{B}\text{E}.\text{dl}$
Now, work done to move a charge aling an equipotential from $A$ to $B$ is zero when potentials at point $A$ and $B$ are some.
Now, work done to move a charge aling an equipotential from $A$ to $B$ is zero when potentials at point $A$ and $B$ are some.
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