There are $8$ equal resistances $R$. Two are connected in parallel, such four groups are connected in series, the total resistance of the system will be
A$R / 2$
B$2 R$
C$4 R$
D$8 R$
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B$2 R$
b (b) Resistance of parallel group $ = \frac{R}{2}$
$\therefore $ Total equivalent resistance $=4 \times \frac{R}{2} = 2R$
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