MCQ
This conversion can be acheived by
- A$NaNH_2, CH_3CHO$
- ✓$NaNH_2, CH_3-CH_2-CH_2-Br$
- C$KOH, CH_3 - CH_2 - Br$
- D$KOH,$ $\begin{array}{*{20}{c}}
{C{H_2} - C{H_2}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,} \\
{\,\,Br\,\,\,\,\,\,\,Br\,\,\,\,\,\,\,}
\end{array}$
