Three capacitors of capacity ${C_1},\;{C_2}\;{C_3}$ are connected in series. Their total capacity will be
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(c) $\frac{1}{{{C_R}}} = \frac{1}{{{C_1}}} + \frac{1}{{{C_2}}} + \frac{1}{{{C_3}}}$ $==>$ ${C_R} = {(C_1^{ - 1} + C_2^{ - 1} + C_3^{ - 1})^{ - 1}}$
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