a
(a)
$\because$ Rate of flow will be same across all pipes
So, pressure across the pipe $\propto \frac{\text { length }}{(\text { radius })^4}$ $\quad \quad\{$ rate of flow of liquid (Q) $Q=\frac{\pi P r^4}{8 \eta L}$
$\frac{P_1}{P_2}=\frac{\left(L / r^4\right)}{\left(\frac{L / 2}{(r / 2)^4}\right)}=\frac{1}{8}$
Then $P_2=8 P_1$
