MCQ
Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces ? Also name the triangle formed by the forces as sides
  • $60^{\circ}$ equilateral triangle
  • B
    $120^{\circ}$ equilateral triangle
  • C
    $120^{\circ}, 30^{\circ}, 30^{\circ}$ an isosceles triangle
  • D
    $120^{\circ}$ an obtuse angled triangle

Answer

Correct option: A.
$60^{\circ}$ equilateral triangle
(a) In $N$ forces of equal magnitude works on a single point and their resultant is

Image

zero then angle between any two forces is given$\theta=\frac{360}{N}=\frac{360}{3}=120^{\circ}$If these three vectors are represented by three sides of triangle then they form equilateral triangle

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