
i.e.,
$\theta_{B}=\theta_{A}=20^{\circ} C$
Heat flowing through $D B$ per second $=$ heat flowing through
i.e., $\frac{K A\left(90^{\circ}-20^{\circ}\right)}{I_{B D}}=\frac{K A\left(20^{\circ}-0^{\circ}\right)}{I_{B C}}$
$\therefore \frac{I_{B C}}{I_{B D}}=\frac{2}{7}$
