Three identical capacitors are combined differently. For the same voltage to each combination, the one that stores the greatest energy is
A
Two in parallel and the third in series with it
B
Three in series
C
Three in parallel
D
Two in series and third in parallel with it
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C
Three in parallel
c (c) $U = \frac{1}{2}C{V^2}$
Now if $V$ is constant, then $U$ is greatest when $'Ceq'$ is maximum. This is when all the three are in parallel.
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