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Electrostatics — Physics STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 SciencePhysicsElectrostatics1 Mark
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Answer

Correct option: B.
$\frac{11 \epsilon_0 A}{18 d}$
(b) :$
\begin{gathered}
C_p=C_1+C_2+C_3=\frac{\epsilon_0 A}{3 d}+\frac{\epsilon_0 A}{3(2 d)}+\frac{\epsilon_0 A}{3(3 d)} \\
=\frac{\epsilon_0 A}{3 d}+\frac{\epsilon_0 A}{6 d}+\frac{\epsilon_0 A}{9 d}=\frac{11 \epsilon_0 A}{18 d}
\end{gathered}
$

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