Three particles, each having a charge of $10\,\mu C$ are placed at the corners of an equilateral triangle of side $10\,cm$. The electrostatic potential energy of the system is.....$J$ (Given $\frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {10^9}\,N - {m^2}/{C^2}$)
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A parallel plate capacitor has plates with area $A$ and separation $d$ . A battery charges the plates to a potential difference $V_0$ . The battery is then disconnected and a dielectric slab of thickness $d$ is introduced. The ratio of energy stored in the capacitor before and after the slab is introduced, is
Two metallic plates form a parallel plate capacitor. The distance between the plates is $'d'.$ A metal sheet of thickness $\frac{d}{2}$ and of area equal to area of each plate is introduced between the plates. What will be the ratio of the new capacitance to the original capacitance of the capacitor $?$
In the circuit shown in figure $C_1=2C_2$. Switch $S$ is closed at time $t=0$. Let $i_1$ and $i_2$ be the currents flowing through $C_1$ and $C_2$ at any time $t$, then the ratio $i_1/ i_2$
The electric potential in volts due to an electric dipole of dipole moment $2 \times 10^{-8}$ coulomb-metre at a distance of $3 \,m$ on a line making an angle of $60^{\circ}$ with the axis of the dipole is ..........
Two capacitors $C_1 = 4\ \mu F$ and $C_2 = 2\ \mu F$ are charged to same potential $ V = 500\ Volt$, but with opposite polarity as shown in the figure. The switches $S_1$ and $S_2$ are closed.
An infinite number of identical capacitors each of capacitance $1\,\mu F$ are connected as in adjoining figure. Then the equivalent capacitance between $A$ and $B$ is......$\mu F$