Three capacitors $1, 2$ and $4\,\mu F$ are connected in series to a $10\,volt$ source. The charge on the plates of middle capacitor is
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$\frac{1}{C}=1+\frac{1}{2}+\frac{1}{4}=\frac{7}{4} \Rightarrow C=\frac{4}{7}\, \mu F$
$\mathrm{Q}=\mathrm{CV}=\frac{4}{7} \times 10=\frac{40}{7}\, \mu \mathrm{C}$
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