MCQ
Three solutions of $HCl$ having normalities $12\ N, 6\ N$ and $2\ N$ are mixed to obtain a solution of $4\ N$ normality. Which among the following volume ratio is incorrect for the above discussion
- A$1: 1: 5$
- B$1 :2: 6$
- C$2: 1: 9$
- ✓$1: 2: 4$
✓
Answer
Correct option: D.
$1: 2: 4$
d
$\mathrm{N}_{1} \mathrm{V}_{1}+\mathrm{N}_{2} \mathrm{V}_{2}+\mathrm{N}_{3} \mathrm{V}_{3}=\mathrm{N}_{\mathrm{R}}\left(\mathrm{V}_{1}+\mathrm{V}_{2}+\mathrm{V}_{3}\right)$
$\mathrm{N}_{1} \mathrm{V}_{1}+\mathrm{N}_{2} \mathrm{V}_{2}+\mathrm{N}_{3} \mathrm{V}_{3}=\mathrm{N}_{\mathrm{R}}\left(\mathrm{V}_{1}+\mathrm{V}_{2}+\mathrm{V}_{3}\right)$
$12 \times 1+6 \times 2+2 \times 6=N_{R}(9)$
$\mathrm{N}_{\mathrm{R}}=4$
Similarly $1: 1: 5 \&: 2: 1: 9$ will also give.
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