Three uncharged capacitors of capacitance C_1, C_2 and C_3 are connected as shown in figure to one another and to points A, B and D

Q: Three uncharged capacitors of capacitance $C_1$, $C_2$ and $C_3$ are connected as shown in figure to one another and to points $A$, $B$ and $D$ at potentials $V_A$, $V_B$ and $V_D$. Then the potential at $O$ will be

b $\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{0}=\frac{\mathrm{q}}{\mathrm{C}_{1}} \quad$ or $\mathrm{q}=\left(\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{0}\right) \mathrm{C}_{1}$ $\mathrm{V}_{\mathrm{B}}-\mathrm{V}_{0}=\frac{\mathrm{q}_{1}}{\mathrm{C}_{2}}$ or $\mathrm{q}_{1}=\left(\mathrm{V}_{\mathrm{B}}-\mathrm{V}_{0}\right) \mathrm{C}_{2}$ $\mathrm{V}_{\mathrm{D}}-\mathrm{V}_{0}=\frac{\mathrm{q}_{2}}{\mathrm{C}_{3}} \quad$ or $\quad \mathrm{q}_{2}=\left(\mathrm{V}_{\mathrm{D}}-\mathrm{V}_{0}\right) \mathrm{C}_{3}$ $\mathrm{q}=\mathrm{q}_{1}+\mathrm{q}_{2}$ $\left(\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{0}\right) \mathrm{C}_{1}=\left(\mathrm{V}_{\mathrm{B}}-\mathrm{V}_{\mathrm{o}}\right) \mathrm{C}_{2}+\left(\mathrm{V}_{\mathrm{D}}-\mathrm{V}_{\mathrm{o}}\right) \mathrm{C}_{3}$ $\therefore \mathrm{V}_{0}=\frac{\mathrm{V}_{\mathrm{A}} \mathrm{C}_{1}+\mathrm{V}_{\mathrm{B}} \mathrm{C}_{2}+\mathrm{V}_{\mathrm{D}} \mathrm{C}_{3}}{\mathrm{C}_{1}+\mathrm{C}_{2}+\mathrm{C}_{3}}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

Three uncharged capacitors of capacitance $C_1$, $C_2$ and $C_3$ are connected as shown in figure to one another and to points $A$, $B$ and $D$ at potentials $V_A$, $V_B$ and $V_D$. Then the potential at $O$ will be

A$\frac{{{V_A} + {V_B} + {V_D}}}{{{C_1} + {C_2} + {C_3}}}$
B$\frac{{{V_A}{C_1} + {V_B}{C_2} + {V_D}{C_3}}}{{{C_1} + {C_2} + {C_3}}}$
C$\frac{{{V_A}{V_{\bf{B}}} + {V_B}{V_D} + {V_D}{V_A}}}{{{C_1} + {C_2} + {C_3}}}$
D$\frac{{{V_A}{V_B}{V_D}}}{{{C_1}{C_2} + {C_2}{C_3} + {C_3}{C_1}}}$

Medium

STD 11 Science
NEET
STD 12 - 2. Electric potential and capacitance
Physics

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