MCQ
Three vertices of parallelogram are $(1, 3), (2, 0)$ and $(5, 1)$. Then its fourth vertex is
- A$(3, 3)$
- ✓$(4, 4)$
- C$(4, 0)$
- D$(0, -4)$
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$x^2 + y^2 + 12x -20 y + 120 = 0$