Question
$[Ti(H_2O)]^{3+}$ is coloured while $[Sc(H_2O)_6]^{3+}$ is colourless.
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Answer
This is due to d-d transition of electron in $[Ti(H_2O)]^{3+}$ complex $Ti^{3+}$ has one electron in d-orbital $(3d^1)$ which absorb energy corresponding to blue-green region and jumps from $t_{2g}$ to $e_g$ set of d-orbitals $\big(\text{t}^1_{2\text{g}}\text{ e}^0_{\text{g}}\xrightarrow{\ \ \ \ \ }\text{t}^0_{2\text{g}}\text{ e}^1_{\text{g}}\big).$ But $Sc^{3+}$ has no electron in the d-orbital.
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