Time period of a simple pendulum is T. The angular displacement f… - Vidyadip

MCQ

Time period of a simple pendulum is $T$. The angular displacement for amplitude is $\beta$. How much time the bob of pendulum will take to move from equilibrium position $O$ to $A$, making an angle $\alpha$ at the support

A
$T\,{\sin ^{ - 1}}\left( {\frac{\alpha }{\beta }} \right)$
B
$T\,{\sin ^{ - 1}}\left( {\frac{\beta }{\alpha }} \right)$
✓
$\frac{T}{2\pi }\,{\sin ^{ - 1}}\left( {\frac{\alpha }{\beta }} \right)$
D
$\frac{T}{\pi }\,{\sin ^{ - 1}}\left( {\frac{\alpha }{\beta }} \right)$

✓

Answer

Correct option: C.

$\frac{T}{2\pi }\,{\sin ^{ - 1}}\left( {\frac{\alpha }{\beta }} \right)$

c

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