MCQ
Time period of a simple pendulum is $T$. The time taken to complete $5 / 8$ oscillations starting from mean position is $\frac{\alpha}{\beta} T$. The value of $\alpha$ is ..... .
- A$5$
- B$3$
- ✓$7$
- D$6$
✓
Answer
Correct option: C.
$7$
c
$\frac{5}{8}$ th of oscillation $=\left(\frac{1}{2}+\frac{1}{8}\right)^{\text {th }}$ of oscillation
$\frac{5}{8}$ th of oscillation $=\left(\frac{1}{2}+\frac{1}{8}\right)^{\text {th }}$ of oscillation
$\pi+\theta=\omega t$
$\pi+\frac{\pi}{6}=\left(\frac{2 \pi}{T}\right) t$
$\frac{7 \pi}{6}=\left(\frac{2 \pi}{T}\right) t$
$t=\frac{7 T}{12}$
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