MCQ
$\triangle ABC $ માં,જો $cot\frac{A}{2}cot\frac{B}{2}=c,cot\frac{B}{2}cot\frac{C}{2}=a$ અને $cot\frac{C}{2}cot\frac{A}{2}=b,$ તો $\frac{1}{s-a}+\frac{1}{s-b}+\frac{1}{s-c}=:$
- A4
- B3
- C6
- ✓2
$cot\frac{A}{2}cot\frac{B}{2}=c$
$\Rightarrow \sqrt{\frac{s(s-a)}{(s-b)(s-c)}}\sqrt{\frac{s(s-b)}{(s-c)(s-a)}}=c$
$\Rightarrow \frac{s}{s-c}=c$
$\Rightarrow \frac{1}{s-c}=\frac{c}{s}.$
તેવી જ રીતે $\frac{1}{s-a}=\frac{a}{s}$ અને $\frac{1}{s-b}=\frac{b}{s}.$
ઉમેરતા $\frac{1}{s-a}+\frac{1}{s-b}+\frac{1}{s-c}=\frac{a+b+c}{s}=\frac{2s}{s}=2.$
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