Question
$\triangle \text{ABC}$ में क्रमशः $\overrightarrow{ AB }, \overrightarrow{ BC }, \overrightarrow{ CA }$ से निरूपित तीन सदिशों का योग लिखिए।

Answer

$\overrightarrow{ AB }+\overrightarrow{ BC }+\overrightarrow{ CA }=(\overrightarrow{ AB }+\overrightarrow{ BC })+\overrightarrow{ CA }$
$=\overrightarrow{ AC }+\overrightarrow{ CA }$
$=\overrightarrow{ AC }-\overrightarrow{ AC }$
$=\vec{0}$

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