c
The formula for the pressure exerted by the liquid on the base is,

\(P=\rho g h\)

Rewrite the above equation.

\(P=\left(\frac{m}{V}\right) g h\)

\(P=\left(\frac{m}{A \times h}\right) g h\)

\(P=\frac{g m}{A}\)

The force exerted by the liquid is,

\(F=P \times A\)

\(F=\left(\frac{g m}{A}\right) \times A\)

\(F=g m\)

since the mass of the \(A, B\) and \(C\) are equal.

Therefore, \(F_{A}=F_{B}=F_{C}\)