The charge \(-2 q\) is placed at the origin \(\mathrm{O}\). One \(+q\) charge is place at \((a, 0,0)\) and the other \(+q\) charge is placed at \((0, a, 0) .\) Thus the system has two dipoles along \(x-\)axis and \(y-\)axis respectively.
As the electric dipole moment is directed from the negative to the positive charge hence the resultant dipole moment will be hong \(\overline{\mathrm{OA}}\) where co-ordinates of point \(\mathrm{A}\) are \((a, a, 0) .\) The magnitude of each dipolemoment,
\(p=q a\)
So, the magnitude of resultant dipole moment is
\(\mathrm{P}_{\mathrm{R}}=\sqrt{\mathrm{p}^{2}+\mathrm{p}^{2}}=\sqrt{(\mathrm{qa})^{2}+(\mathrm{qa})^{2}}\)
\(=\sqrt{2}\, \mathrm{qa}\)