==> \(\frac{{{v_{\max }}}}{v} = \frac{{\omega a}}{{\omega /k}} = ka\).
From the given equation \(k = {\rm{Co - efficient}}\;{\rm{of}}\,x = 6\,micron\)
\(\; = 6 \times {10^{ - 6}}m\)
==> \(\frac{{{v_{\max }}}}{v} = ka = 6 \times {10^{ - 6}} \times 60 = 3.6 \times {10^{ - 4}}\)
(જયાં $ {I_0} $ થ્રેશોલ્ડ તીવ્રતા)