Tube $A$ has both ends open while tube $B$ has one end closed, otherwise they are identical. The ratio of fundamental frequency of tube $A$ and $B$ is
AIEEE 2002, Medium
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(c) ${n_A} = \frac{v}{{2l}};\;{n_B} = \frac{v}{{4l}} \Rightarrow {n_A}/{n_B} = 2:1$
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