MCQ
Two balls are projected upward simultaneously with speeds $40 \,m / s$ and $60 \,m / s$. Relative position $(x)$ of second ball w.r.t. first ball at time $t=5 s$ is .......... $m$ [Neglect air resistance].
  • A
    $20$
  • B
    $80$
  • $100$
  • D
    $120$

Answer

Correct option: C.
$100$
c
(c)

$S_{ rel }=U_{ rel } t+\frac{1}{2} a_{ rel } t^2$

$\Rightarrow S_{ rel }=(60-40) 5 \quad\left(a_{ rel }=0\right)$

$\Rightarrow S_{ rel }=100 \,m$

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