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6. system of particles and rotational motion — Physics STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 SciencePhysics6. system of particles and rotational motion1 Mark
MCQ
Two bodies, a ring and a solid cylinder of same material are rolling down without slipping an inclined plane. The radii of the bodies are same. The ratio of velocity of the centre of mass at the bottom of the inclined plane of the ring to that of the cylinder is $\frac{\sqrt{x}}{2}$. Then, the value of $x$ is .... .
  • A
    $1$
  • ✓
    $3$
  • C
    $9$
  • D
    $10$
✓

Answer

Correct option: B.
$3$
b
${I}$ in both cases is about point of contact $IAOR,$

Ring,

$m g h=\frac{1}{2} I \omega^{2}$

$m g h=\frac{1}{2}\left(2 m R^{2}\right) \frac{v_{R}^{2}}{R^{2}}$

$V_{R}=\sqrt{g h}$

Solid, cylinder

$m g h=\frac{1}{2} I \omega^{2}$

$m g h=\frac{1}{2}\left(\frac{3}{2} m R^{2}\right) \frac{v_{c}^{2}}{R^{2}}$

$V_{R}=\sqrt{\frac{4 g h}{3}}$

$\frac{v_{R}}{v_{c}}=\frac{\sqrt{3}}{2}$

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