Two capacitors, each having capacitance 40 , F are connected in s… - Vidyadip

MCQ

Two capacitors, each having capacitance $40\,\mu F$ are connected in series. The space between one of the capacitors is filled with dielectric material of dielectric constant $K$ such that the equivalence capacitance of the system became $24\,\mu F$. The value of $K$ will be.

✓
$1.5$
B
$2.5$
C
$1.2$
D
$3$

✓

Answer

Correct option: A.

$1.5$

a
$C _{ eq }=\frac{ C ( KC )}{ C + KC }=\frac{ KC }{ K +1}$

$24=\frac{K 40}{K+1}$

${[K=1 \cdot 5] }$

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