Question
Two capacitors each having capacitance C and breakdown voltage V are joined in series. The capacitance and the breakdown voltage of the combination will be:
- $\text{2C}\ \text{and}\ \text{2V}$
- $\frac{\text{C}}{2}\ \text{and}\ \frac{\text{V}}{2}$
- $\text{2C}\ \text{and}\ \frac{\text{V}}{2}$
- $\frac{\text{C}}{2}\ \text{and}\ \text{2V}$
