Two capacitors of $2$ $\mu F$ and $3$ $\mu F$ are charged to $150$ $volt$ and $120$ $volt$ respectively. The plates of capacitor are connected as shown in the figure. A discharged capacitor of capacity $1.5$ $\mu F$ falls to the free ends of the wire. Then
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Charge in $2 \mu F$ Capacitor $=300 \mu C$
Charge in $3 \mu F$ Capacitor $=360 \mu C$
when $1.5 \mu F$ falls on the circuit ends, $Re-distribution$ of charge now will be$:$
Charge in $2 \mu F$ Capacitor $=300-x \mu C$ Charge in $3 \mu F$
Capacitor $=360-x \mu C$ Charge in $1.5 \mu F$ Capacitor $=x \mu C$
By Kirchoff Voltage Law$:$
$\frac{x}{1.5}=\frac{300-x}{2}+\frac{360-x}{3}$
which gives $x=180 \mu C$
Therefore Answers are $A, B \& C$
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