Two charges of $4\,\mu C$ each are placed at the corners $A$ and $B $ of an equilateral triangle of side length $0.2\, m $ in air. The electric potential at $C$ is $\left[ {\frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {{10}^9}\,\frac{{N{\rm{ - }}{m^2}}}{{{C^2}}}} \right]$
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(c) Potential at C $ = \left( {9 \times {{10}^9} \times \frac{{4 \times {{10}^{ - 6}}}}{{0.2}}} \right) \times 2= 36 \times 10^4 \,V$
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